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8k^2-6=-4k
We move all terms to the left:
8k^2-6-(-4k)=0
We get rid of parentheses
8k^2+4k-6=0
a = 8; b = 4; c = -6;
Δ = b2-4ac
Δ = 42-4·8·(-6)
Δ = 208
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{208}=\sqrt{16*13}=\sqrt{16}*\sqrt{13}=4\sqrt{13}$$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4)-4\sqrt{13}}{2*8}=\frac{-4-4\sqrt{13}}{16} $$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4)+4\sqrt{13}}{2*8}=\frac{-4+4\sqrt{13}}{16} $
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